lim (n→∞) (1/n) Σ[k=1 to n] (k/n) = ?
A
1/2
B
1
C
0
D
2/3
Analysis & Theory
This is ∫[0 to 1] x dx = [x²/2]₀¹ = 1/2.
lim (n→∞) (1/n) Σ[k=1 to n] (k/n)² = ?
A
1/3
B
1/2
C
2/3
D
1/4
Analysis & Theory
This is ∫[0 to 1] x² dx = [x³/3]₀¹ = 1/3.
lim (n→∞) (π/n) Σ[k=1 to n] sin(kπ/n) = ?
A
2
B
π/2
C
0
D
1
Analysis & Theory
This is ∫[0 to π] sin(x) dx = 2.
lim (n→∞) (1/n) Σ[k=1 to n] (1 + k/n) = ?
A
3/2
B
2
C
1
D
1/2
Analysis & Theory
This is ∫[0 to 1] (1 + x) dx = [x + x²/2]₀¹ = 1 + 1/2 = 3/2.
lim (n→∞) (1/n) Σ[k=1 to n] √(k/n) = ?
A
2/3
B
1/2
C
1
D
√2
Analysis & Theory
This is ∫[0 to 1] √x dx = [2/3 x^(3/2)]₀¹ = 2/3.
lim (n→∞) (1/n) Σ[k=1 to n] (k/n)³ = ?
A
1/4
B
1/3
C
1/2
D
1
Analysis & Theory
This is ∫[0 to 1] x³ dx = [x⁴/4]₀¹ = 1/4.
lim (n→∞) (π/2n) Σ[k=1 to n] cos(kπ/2n) = ?
A
1
B
π/2
C
2
D
0
Analysis & Theory
This is ∫[0 to π/2] cos(x) dx = 1.
lim (n→∞) (1/n) Σ[k=1 to n] e^(k/n) = ?
A
e - 1
B
1
C
e
D
2
Analysis & Theory
This is ∫[0 to 1] e^x dx = [e^x]₀¹ = e - 1.
lim (n→∞) (2/n) Σ[k=1 to n] (k/n) = ?
A
2/2 = 1
B
2
C
4/3
D
1/2
Analysis & Theory
This is ∫[0 to 2] x dx = [x²/2]₀² = 2.
lim (n→∞) (3/n) Σ[k=1 to n] (k/n)² = ?
A
1
B
3
C
1/3
D
2
Analysis & Theory
This is ∫[0 to 3] (x²/9) *3 dx ? Careful → Rewrite: (3/n)(k/n)² = (3/n³)k². Limit → ∫[0 to 3] (x²/9) dx = [x³/27]₀³ = 1.